Level UpStart free trial

7th Grade · 7.EE.B.3

Multi-step word problems in 7th grade

Multi-step word problems take more than one calculation to solve. In 7th grade, one problem can mix negative numbers, fractions and decimals. Your child learns to plan the steps, switch numbers to an easier form and use estimation to check that the answer makes sense.

What the standard says

The official Common Core wording, quoted exactly. The plain version follows.

7.EE.B.3 Solve multi-step real-life and mathematical problems posed with positive and negative rational numbers in any form (whole numbers, fractions, and decimals), using tools strategically. Apply properties of operations to calculate with numbers in any form; convert between forms as appropriate; and assess the reasonableness of answers using mental computation and estimation strategies.

What it means, in plain words

Multi-step word problems in 7th grade might combine a price in dollars and cents, a discount given as a fraction and a temperature below zero. Your child decides which operations to do and in what order. Writing one expression for the whole story before calculating keeps the steps in the right order.

Switching between forms is part of the skill. A fraction, a decimal and a percent can name the same amount: 14=0.25\frac{1}{4} = 0.25, which is 25%. Your child picks the form that makes the arithmetic easiest, so taking 25% off a price becomes taking a quarter off. The order of multiplication can change too: 4×7×2.54 \times 7 \times 2.5 is easier as (4×2.5)×7=10×7=70(4 \times 2.5) \times 7 = 10 \times 7 = 70.

Estimation is the check at the end. Your child rounds the numbers to friendly ones and works out a rough answer mentally. If the exact answer is far from the estimate, a step went wrong. The goal is a habit of asking whether an answer is reasonable before writing it down.

Your child should be able to:

  • Plan the steps of a word problem and write them as one expression
  • Calculate with positive and negative whole numbers, fractions and decimals in the same problem
  • Switch between fractions, decimals and percents when one form is easier
  • Use estimation to check whether an answer is reasonable

Example

A jacket costs 60 dollars. It is on sale for one quarter off, and a 5% sales tax is added to the sale price. What does the jacket cost?

  1. One quarter of 60 is 60÷4=1560 \div 4 = 15, so the sale price is 60−15=4560 - 15 = 45 dollars.
  2. The tax is 5% of 45: 0.05×45=2.250.05 \times 45 = 2.25 dollars.
  3. Total: 45+2.25=47.2545 + 2.25 = 47.25.
  4. Estimate: 5% of about 40 is 2, so the total should be a little over 47 dollars. The jacket costs 47.25 dollars.

Example

The low temperatures on four nights were −3.5-3.5, 22, −6-6 and −0.5-0.5 degrees Celsius. What was the mean low temperature?

  1. Add the four temperatures: −3.5+2+(−6)+(−0.5)=−8-3.5 + 2 + (-6) + (-0.5) = -8.
  2. Divide by the number of nights: −8÷4=−2-8 \div 4 = -2.
  3. Estimate: three of the four nights were below zero, so a negative mean makes sense.
  4. The mean low temperature was −2-2 degrees Celsius.

Where children usually get stuck

  • For "one quarter off" a 60-dollar jacket, your child writes 60−0.25=59.7560 - 0.25 = 59.75.

    The fraction is read as an amount of money, not as a part of the price. One quarter off means one quarter of 60, which is 15 dollars off.

    What helps. Before your child calculates, ask "a quarter of what?" The answer is "of the price", and that tells your child to divide the price by 4 first.

  • Your child adds −6-6 and 22 and gets −8-8 or 88.

    Adding a negative and a positive number is still shaky, so your child adds the sizes of the numbers and then guesses the sign.

    What helps. Picture a thermometer. Start at −6-6 and go up 2 degrees, and you land on −4-4.

  • Your child gets 472.50 dollars for the jacket and writes it down as the answer.

    A decimal point slipped, and nothing prompted your child to look back. Estimation is often practiced as a separate exercise, so it does not become a habit at the end of each problem.

    What helps. Before any calculation, ask for a guess: "About how much?" Write the guess next to the problem and compare it with the final answer.

Try four practice questions

Real 7th grade questions from our question bank, easiest first. Answer them right here, check each one, and see a worked solution for any question.

  1. 1Warm-up
    Evaluate the expression. Type the exact value as a number.
    3(12+0.3)\displaystyle 3\left(\frac{1}{2} + 0.3\right)
    Exact value:
    Show the answer and how to solve it

    Answer. 2.4

    The answer is 2.4 because the parentheses equal 0.8 and 3×0.8=2.43 \times 0.8 = 2.4.

    1. 1Start with the expression inside the parentheses because grouping symbols come first.
    2. 2Convert 12\frac{1}{2} to 0.50.5, then add inside the parentheses to get 0.80.8.
    3. 3Multiply 33 by 0.80.8 to get the final answer.

    Common mistake. A common mistake is adding 3+0.5+0.33 + 0.5 + 0.3 instead of multiplying. Remember the coefficient 3 multiplies the entire grouped result: the parentheses equal 0.8 first, then 3×0.8=2.43 \times 0.8 = 2.4.

    The idea underneath. Parentheses make part of an expression act like one number; once you replace that group with its value, the rest of the order of operations is easier to follow.

  2. 2On level
    Match each expression to the estimate that is closest to its value. One estimate will not be used.
    Connect each item on the left to its match on the right.
    Expression
    Best estimate
    35−0.1+0.05\displaystyle \frac{3}{5} - 0.1 + 0.05
    −910−0.2+0.1\displaystyle -\frac{9}{10} - 0.2 + 0.1
    310−0.4+0.1\displaystyle \frac{3}{10} - 0.4 + 0.1
    0\displaystyle 0
    12\displaystyle \frac{1}{2}
    −1\displaystyle -1
    1\displaystyle 1

    Use Tab to navigate between items. Click or tap a card to select it, then click or tap a card on the opposite side to create a match. You can also drag a card or its connector dot to a card on the opposite side.

    Show the answer and how to solve it

    Match 35−0.1+0.05\frac{3}{5} - 0.1 + 0.05 with 12\frac{1}{2}, match −910−0.2+0.1-\frac{9}{10} - 0.2 + 0.1 with −1-1, and match 310−0.4+0.1\frac{3}{10} - 0.4 + 0.1 with 00. The estimate 11 is not used.

    1. 1The available estimates are 00, 12\frac{1}{2}, −1-1, and 11. For each expression, replace each rational number with a nearby friendly value and decide which benchmark the total is closest to.
    2. 235\frac{3}{5} is about 0.60.6, so the first expression is approximately 0.6−0.1+0.05=0.550.6 - 0.1 + 0.05 = 0.55. The closest estimate is 12\frac{1}{2}.
    3. 3Keep the negative sign on −910-\frac{9}{10}. It is about −0.9-0.9, so the second expression is approximately −0.9−0.2+0.1=−1.0-0.9 - 0.2 + 0.1 = -1.0. The closest estimate is −1-1.
    4. 4310\frac{3}{10} is about 0.30.3, so the third expression is approximately 0.3−0.4+0.1=00.3 - 0.4 + 0.1 = 0. The closest estimate is 00.

    Common mistake. A common mistake is dropping the negative sign in −910-\frac{9}{10} and treating the second expression as about 0.80.8, then incorrectly matching it to 11 instead of −1-1.

    The idea underneath. A strong estimate comes from replacing each rational number with a nearby friendly value and then deciding which displayed benchmark the total is closest to.

  3. 3On level
    You owe a friend $4.85. After earning $12.15 helping with yard work and spending $6.20 on lunch, which is the best estimate of your balance now?
    A
    0\displaystyle 0
    B
    1\displaystyle 1
    C
    7\displaystyle 7
    D
    11\displaystyle 11
    Show the answer and how to solve it

    The answer is 1 because the amounts round to -5, 12, and -6, and −5+12−6=1-5 + 12 - 6 = 1, so the balance is about $1.

    1. 1Translate the story into signed numbers: the debt is negative, earning is positive, and spending is negative.
    2. 2Round each amount to a nearby whole number.
    3. 3Combine the rounded numbers.
    4. 4So the best estimate is the option showing 1.

    Common mistake. A common mistake is dropping the starting debt and estimating only 12.15−6.20≈612.15 - 6.20 \approx 6 or 7. Always include the opening debt as a negative amount before combining the later changes.

    The idea underneath. In signed real-life problems, decide whether each amount adds to or subtracts from the total before you round.

  4. 4Stretch
    A player's score is 1515 points. In each of 33 rounds, the player earns 44 points then loses 1.51.5 points. After all the rounds, the player loses 55 more points. Using the numbers from the story, write the calculation only. Do not solve or simplify.
    Loading...
    Show the answer and how to solve it

    Answer. 15+3\left(4-1.5\right)+\left(-5\right)

    One correct calculation is 15+3(4−1.5)+(−5)15 + 3(4 − 1.5) + (−5) because it starts at 15, shows 3 grouped rounds of earning 4 and losing 1.5, and then subtracts 5 without solving.

    1. 1The starting score is 15.
    2. 2Each round has two changes: earning 4 points and losing 1.5 points. Both happen within the same round, so they must be grouped together as (4 − 1.5). Parentheses are required to show that both changes belong to each round.
    3. 3That combined change repeats 3 times, so write 3(4 − 1.5).
    4. 4After the rounds, the player loses 5 more points. A loss is a negative change, so add −5.
    5. 5Put all parts together and stop there, because the problem asks for the calculation only.

    Common mistake. A common mistake is writing 15+3×415 + 3 \times 4 − 1.5 + (−5) instead of 15+3(4−1.5)+(−5)15 + 3(4 − 1.5) + (−5), which applies the 3 only to the 4-point gain and ignores the 1.5-point loss. Both changes happen every round, so both must be inside the parentheses. Another mistake is simplifying 4 − 1.5 to 2.5 before writing the expression.

    The idea underneath. Repeated change is shown by multiplying the number of repeats by the signed change, then combining that with the start and final adjustment.